Sending a string with quotation mark in bash script

Question

How to pass whole string also with quotation marks.

#!/bin/bash

my_name="My Value"

function abc(){
    a=$1
    echo $a
}

abc $my_name

This gives :

My

How to get the value as :

"My value"

also with quotation marks

The variable doesn't *have* quotation marks; the value of `my_name` is literally `My Value`; the quotes only exist to tell the shell that the space is part of the value, not separating the assignment `my_name=My` from the command `Value`. — chepner, Jul 24 '20 at 16:03
Long discussion at [Security implications of forgetting to quote a variable in bash/POSIX shells](https://unix.stackexchange.com/questions/171346/security-implications-of-forgetting-to-quote-a-variable-in-bash-posix-shells) — glenn jackman, Jul 24 '20 at 16:04

Midha Tahir · Answer 1 · 2020-07-24T16:03:53.360

1

Try enclosing in quotes instead of abc $my_name

abc "$my_name"

If you want quotes in your output too then try defining as:

my_name="\"My Value\""

and then type:

abc "$my_name"

edited Jul 24 '20 at 16:03

answered Jul 24 '20 at 15:57

Midha Tahir

score 1 · Answer 2 · edited Jul 24 '20 at 16:06

1

The easiest way to do this is to pass your argument within single quotes. This will consider your whole argument as a single string. Try this:

#!/bin/bash

my_name='"My Value"'

function abc(){
    a=$1
    echo "$a"
}

abc "$my_name"

edited Jul 24 '20 at 16:06

chepner

answered Jul 24 '20 at 15:58

Kebby

Is it safe on surrounding the sql queries with single quote ' , as need to pass the whole "select .." with quotes – supernatural Jul 24 '20 at 16:01

2 Answers2