In Python, how do I append the integer 19 to a list of two digit years?

Asked Jul 24 '20 at 17:10

Active Jul 24 '20 at 17:12

Viewed 22 times

I am importing a data file where the years are two digit integers. So 1982 is 82. Using csv reader, I would like to prepend the integer 19 to the years. Here is the for loop I am using. It works great. I just want to prepend 19. ('19'+int(record.year) gives me a string error. Here is my code.

with open('auto.clean.txt') as f:
            reader = csv.reader(f, delimiter= ' ', skipinitialspace=True)
            for row in reader:
                record = Record(row[0], row[1], row[2],row[3],row[4],row[5],row[6],row[7],row[8])
                tokens = record.car_name.split(' ')
                make = tokens[0]
                model = ' '.join(tokens[1:])              
                r = AutoMPG(make, model, (int(record.year)), float(record.mpg))
                self.data.append(r)

edited Jul 24 '20 at 17:12

OneCricketeer

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asked Jul 24 '20 at 17:10

Timothy Elliott

Welcome to StackOverflow. In the future, please create a [mcve] of the problem you are having – OneCricketeer Jul 24 '20 at 17:13
You have to do `str(19) + record.year`. – Andrej Jul 24 '20 at 17:15
You can do the concatenation with strings, with `'19' + string_year` or in integer form `1900 + int(string_year)`. Which is best depends what you intend to do with the year afterwards. – Blckknght Jul 24 '20 at 17:20
That was it. Thanks guys! – Timothy Elliott Jul 24 '20 at 17:26

In Python, how do I append the integer 19 to a list of two digit years?

0 Answers0