If i have a float number like float = 51.31876543.
How can I create a new float value selecting the first seven numbers and generating randomly the remain numbers? To obtain something like this:
float = 51.31876 + 3 random numbers
like 51.31876411 or 51.31876739 ...
you can convert your float number to a string and then add your 3 random numbers.
first, let's see how you can make your random numbers: by using random library. I suggest random.randint().
import random
f = 51.31876543
# now you must choose the first seven numbers that you have in mind.
f_str = str(f)[:8]
# we assume that your number is always a float.
# if you were not sure if it is an integer or a float, you can code this:
if '.' not in f_str:
f_str.pop()
# now make your random 3 number and add it to your number:
f_str = f_str + str(random.randint(100, 999))
f = float(f_str) # change type from string to float.
You can use the truncate function defined here to get just the 5 decimal values, multiply it by 100.000, sum with a random int between 100 and 999, divide it by 100.000 and the rounding up to 5 decimal values again.
def truncate(f, n):
'''Truncates/pads a float f to n decimal places without rounding'''
s = '{}'.format(f)
if 'e' in s or 'E' in s:
return '{0:.{1}f}'.format(f, n)
i, p, d = s.partition('.')
return '.'.join([i, (d+'0'*n)[:n]])
import random
float = 51.31876543
float = truncate(float, 5)
float = float * 10e5
random_3_numbers = random.randint(100,999)
float += random_3_numbers
float /= 10e5
float = truncate(float, 5)
Also, your question is badly tagged. It should contain python and other tags as well.
Here is how you can use random.randint():
from random import randint
f = 51.31876543
f = str(f)[:8]
if '.' not in f:
f.pop()
for _ in range(3):
f += str(randint(0,9))
print(f)
Output:
51.31876308
