How do I rectify 'Unexpected Indent" error in Python?

Question

Here is my code:

def c_to_f(c):    
    f = c*(9/5) + 32
    return f
    
c = input("Please enter the temperature in celsius: ")
    if c< -273.15:
        return "That temperature is not achievable."
    else:
        return f
print("Here's your temperature in Fahrenheit: ", c_to_f(c))

The terminal, on executing this code displays:

if c< -273.15:                                                                                                                            
    ^                                                                                                                                         
IndentationError: unexpected indent

How do I proceed to solve this error?

it means your ```if c< -273.15:``` loop is indented when it shouldn't — ewokx, Jul 31 '20 at 05:49

de_classified · Answer 1 · 2020-07-31T06:03:59.117

0

Need to fix the line above the traceback line it's throwing:

def c_to_f(c):    
    f = c*(9/5) + 32
    print(f)

    # the input line here needs to be indented to be consistent within your code block and consider adding an int() if you are expecting a value
    c = int(input("Please enter the temperature in celsius: "))
    if c < -273.15:
        print("That temperature is not achievable.")
    else:
        print(f)

    # and the print() statement needs to be indented as well 
    print("Here's your temperature in Fahrenheit: ", c_to_f(c))

See this link, it follows the PEP8 rules for indentation (4 spaces).

edited Jul 31 '20 at 06:03

answered Jul 31 '20 at 05:59

de_classified

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The `return f` just stops all, I thinkg this isn't the good function – azro Jul 31 '20 at 06:03
true, should be using `print()` instead to prevent the function from ending before it reaches the if/else statements. – de_classified Jul 31 '20 at 06:04

How do I rectify 'Unexpected Indent" error in Python?

1 Answers1