Convert string with 6 digits before decimal to Double

Question

I have a string with the value 788597.31 and I am converting this value to double but when I print the variable only 788597 is displayed. I have used std::stod(string) and even stringstream but everytime I get the same previous value. Can anybody help me with this? I want to store this string value in a double varaible.

#include<iostream>
#include<string>
#include<sstream>
using namespace std;

int main()
{
  string s="788597.31";
  double d=stod(s);
  cout<<d<<" ";
  stringstream g;
  double a; 
  g<<s; g>>a;
  cout<<a;

  return 0;
}

Does this answer your question? [C++ string to double conversion](https://stackoverflow.com/questions/4754011/c-string-to-double-conversion) — rhavelka, Jul 31 '20 at 20:36
Check whether the problem is in the string parsing or the output. — Patricia Shanahan, Jul 31 '20 at 22:13

Patricia Shanahan · Answer 1 · 2020-08-01T23:23:49.653

0

The problem is in how you are printing your result, not in the string parsing. This program:

#include <iostream>
using namespace std;

int main() {
    cout << 788597.31 << endl;
    return 0;
}

also prints 788597.

#include <iostream>
#include <iomanip>
using namespace std;

int main() {
    cout << setprecision(10) << 788597.31 << endl;
    return 0;
}

prints 788597.31

If you want to see more than the default 6 significant digits your program needs to say so.

edited Aug 01 '20 at 23:23

answered Jul 31 '20 at 22:47

Patricia Shanahan

25,849
4
38
75

You can check yourself by using setprecision. – Patricia Shanahan Aug 01 '20 at 21:35
Please you run my code and show me. First you need to convert the string to double and then print it. – Sarthak Aug 02 '20 at 08:07
@Sarthak I have shown you how to get more than 6 significant digits in your output. Fix that in your program and carry on from there. – Patricia Shanahan Aug 02 '20 at 08:10

Convert string with 6 digits before decimal to Double

1 Answers1