How to organize lists in list alphabetically?

Question

I have a couple of list in a list sorted like this:

L = [['b','4'].['a','7'],['c','2']]

I want to see if it is possible to arrange the list so that it looks bit like this:

L = [['a','7'],['b','4'],['c','2']]

The first character of each list is placed alphabetically. How might I go about doing this?

Do you guys think this is overkill? `print(sorted(L, key=operator.itemgetter(0)))` — , Aug 04 '20 at 19:00
It's overkill in the sense that you don't need a `key` function to do what you want. — martineau, Aug 04 '20 at 19:33
Alright thank you guys. I am just gonna use a simple L.sort() — , Aug 04 '20 at 19:53

score 3 · Accepted Answer · answered Aug 04 '20 at 18:57

3

You can use .sort() that will sort the list alphabetically

L = [['b','4'],['a','7'],['c','2']]
L.sort()

output: [['a', '7'], ['b', '4'], ['c', '2']]

answered Aug 04 '20 at 18:57

David sherriff

score 2 · Answer 2 · answered Aug 04 '20 at 18:57

2

use method sorted():

L = [['b','4'], ['a', '7'],['c','2']]
print(sorted(L))  # output [['a', '7'], ['b', '4'], ['c', '2']]

answered Aug 04 '20 at 18:57

Tasnuva Leeya

2 Answers2