I've a link in admin-dashboard page which on click shows "doctor-details". Now I want the admin must be able to click on the options link in the table and see full details of the doctor in the same page(I'll probably use modals for this).
So my question is how do I get the ID from the table and send it to another php file for database query?
my code for generating details about doctor(doctor-details.php)
<?php
require('config.php');
$sql = "SELECT * FROM doctor";
$result = mysqli_query($conn, $sql);
$count = mysqli_num_rows($result);
if($count > 0){
while($rows = mysqli_fetch_array($result)){
?>
<tr>
<td><?php echo $rows['id'];?> </td>
<td><?php echo $rows['f_name'];?></td>
<td><?php echo $rows['l_name'];?></td>
<td><?php echo $rows['email'];?></td>
<td><?php echo $rows['contact_number'];?></td>
<td><?php echo $rows['gender'];?></td>
<td><a href=""> Options</a></td>
</tr>
<?php
}
}
?>
and finally my ajax:
$(document).ready(function(){
$("#load-doctor-data").click(function(){
$.ajax({
url: 'views/admin/doctor-details.php',
type: 'POST',
success: function(result){
$("#response-doctor").html(result);
}
});
});
});
//Hide table on login
$("#show-doctor-details").hide();
$(document).ready(function(){
$("#load-doctor-data").click(function(){
$("#show-doctor-details").show();
$("#show-patient-details").hide();
});
});
So, the gist is I want to click on options and show full details of John Doe.