Association in PHP

Question

I'm pretty new in PHP, I started to learn OOP, and I'm trying to learn association, however, my code isn't working, I really don't know why, but the problem is on the line 38, when I call the method Driving, it says that must be one instance of Person, what it means?

Src:

<?php

class Person
{
    private $name;

    public function __construct($name)
    {
        $this->name = $name;
    }

    public function getName(){
        return $this->name;
    }
}

class Car
{

    private $size;
    private $model;

    public function __construct($size, $model)
    {
        $this->size = $size;
        $this->model = $model;
    }

    public function Driving(Person $person)
    {
        echo "The size is: {$this->size}<br>";
        echo "Look at the model of the car: " . $this->model;
        echo "Look at the name of the person: " . $person->getName();
    }
}
$obj1 = new Person("Someone");
$obj2 = new Car("120", "Nothing");
$obj2->Driving($person);

?>

score 1 · Accepted Answer · answered Aug 08 '20 at 15:56

1

Look at your code:

$obj1 = new Person("Someone");
$obj2 = new Car("120", "Nothing");
$obj2->Driving($person);

You used $person but the person object is $obj2.

Use $obj2 instead of $person or rename $obj2 to $person.

answered Aug 08 '20 at 15:56

dan1st

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Not sure a silly typo really deserves an answer :) – Jeto Aug 08 '20 at 16:00
I tried but no succcess – Aug 08 '20 at 16:00
@brunasilvinha same error or what happens? – dan1st Aug 08 '20 at 16:01
Oh, I realized now, the problem was in the variable $obj1, I should call it by $person, and then use it in the method Driving() – Aug 08 '20 at 16:03
Thank you so much, you gave me the idea to solve it – Aug 08 '20 at 16:04
Yes. You can either do this or call `$obj2->Driving($obj1)`. – dan1st Aug 08 '20 at 16:05
Yeah, that's good, thanks – Aug 08 '20 at 16:06

Association in PHP

1 Answers1