Take list element, check if it contains only digits, and if so, convert to int class

Question

I have some math expressions in a list, like ["2", "*", "2"], ["3", "+", "pi"]. Now, I want the list elements that contain ONLY digits to be detected, and be converted to integers. Is there a way to do this?

Just for fun · Answer 1 · 2020-08-09T15:47:33.250

-1

newList = [int(i) for i in oldList if i.isdigit()]

edited Aug 09 '20 at 15:47

answered Aug 09 '20 at 15:10

Just for fun

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You don't need to call `str(i)` on strings. `i.isdigit()` will work fine. – Jasmijn Aug 09 '20 at 15:16
I did that thinking if there will be an int in list beforehand. like [1,'*','2'] – Just for fun Aug 09 '20 at 15:18

Take list element, check if it contains only digits, and if so, convert to int class

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