The argument type 'Future' can't be assigned to the parameter type 'String'

Question

Dart as you can see in the below php code.i am trig to crater variable name "token" of **getTokenValue()and use into tokenaddSingleProduct(productInfo,token,callback)**int thi function as String but i can't use

Future <String> getTokenValue()async{
 final  SharedPreferences sharedPreferences=await SharedPreferences.getInstance();
 final String token=sharedPreferences.getString('token');
 print("accept token : ${token}");
  return token;
}
 final token= getTokenValue();

onPressed: (){
                  addSingleProduct(productInfo,token,callback);   //"token"  The argument type 'Future<String>' can't be assigned to the parameter type 'String'.
                },

You should "await" the getTokenValue() call: final token= await getTokenValue(); — Mihályi Zoltán, Aug 10 '20 at 15:15

score 0 · Answer 1 · answered Aug 10 '20 at 15:25

0

You have to await until you get the string value. So call the function inside button press call

onPressed: ()async{
    String token = await getTokenValue();
    addSingleProduct(productInfo,token,callback);
         }

Hope this fix your issue.

answered Aug 10 '20 at 15:25

towhid

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The argument type 'Future' can't be assigned to the parameter type 'String'

1 Answers1