List Python Problems

Question

I just started learning Python and I encountered this problem:

a = [0, 1]
b = [a]
print(a, b) 

a.pop()
print(a, b)

Result:

[0, 1] [[0, 1]]
[0] [[0]]

Why does this happen and how do I avoid it? I want b = [0, 1]. As far as I understood, the b[0] was linked to a so I used b[a.copy()]. Thanks guys.

Do you know what is this topic called? Is it memory allocation in Python? — Henry N., Aug 11 '20 at 07:22
test code on https://pythontutor.com to see how it uses reference. — furas, Aug 11 '20 at 07:24
It is called variable initialization.. you can search for how to initialize a list.. — Arun Kaliraja Baskaran, Aug 11 '20 at 07:25

score 0 · Answer 1 · answered Aug 11 '20 at 07:24

0

welcome to Python,

if you want all elements of ato be passed to b you can dump them like this:

b = [*a] # is the same as [a[0], a[1], ...... ]

which will lead to b = [0,1]

answered Aug 11 '20 at 07:24

Nano Byte

1 Answers1