char * ptr="coding";
Here ptr is a character pointer which is pointing to the first character of the string enclosed in " ", that is ptr is pointing to address of 'c'.
- In pointers--> * Operator is used to getting the values that are stored on the address pointed by the pointer variable.
So here
On accessing *ptr --> we get the value which is stored in the address pointed by ptr, as ptr is pointing to address of 'c', so on writing this code
char * ptr="coding";
cout<< *ptr;
we get the output: c
on accessing *++ptr --> ++ptr increments the location by 1 , so on accessing *++ptr, we get the value which is stored in next loaction.So on writing this code
char * ptr="coding";
cout<< *++ptr;
we get the output: o
& operator is used for getting the address that is being pointed by pointer variable, here as ptr is pointing to 'c' so on writing this code :
const char* str = "Hello";
cout << &str ;
we get the output: 0x7fff11d19cb0
Now when we write code:
char * ptr="coding";
cout<< ptr;
We get the output: coding
How is it printing a whole string, as ptr is only pointing to the address of the first character 'c'. Where does ptr pointing to? As ptr is a character pointer.
