read file from resource Java

Question

I found this file exist in the url showed, but still get NoSuchFileException. Had try many way but the path return always same, but cant read the file. How it will be? It there but not there? why plz?

 public void readFile() throws IOException {
  
    String fileName = "domain.txt";
    ClassLoader classLoader = getClass().getClassLoader();

    File file = new File(classLoader.getResource(fileName).getFile());

    //File is found
    System.out.println("File Found : " + file.exists());

    //Read File Content
    String content = new String(Files.readAllBytes(file.toPath()));
    System.out.println(content);
}

Have you tried something like this: https://stackoverflow.com/questions/3888226/how-can-i-read-file-from-classes-directory-in-my-war ? And, by the way, you should never post your code as a picture. Paste the code and the output to the question itself, so we can copy it. — default locale, Aug 14 '20 at 04:15
A resource is not a file. You need to use `Class.getResource()` and friends, not a file. Don't post pictures of text here. Post the text. — user207421, Aug 14 '20 at 04:15
@MarquisofLorne sorry, i had edited. But how when i use Class classer = getClass(); URL url = class.getResource("domain.txt"); i get null — VendettaV, Aug 14 '20 at 06:38
Don't call `getFile()`, or create a `File`, or the rest of it. `ClassLoader.getResource()` returns a `URL`: get the input stream directly from that. — user207421, Aug 14 '20 at 07:37

score 0 · Answer 1 · answered Aug 14 '20 at 05:09

When you use ClassLoader you must use absolute path

public void readFile() throws IOException {

    // Must use absolute path here, so start with a slash
    String fileName = "/domain.txt";

    // Use InputStream instead of File
    InputStream input = ClassLoader.getSystemResourceAsStream(filename);
    BufferedReader bf = new BufferedReader(new InputStreamReader(input));

    String line = null;
    StringBuilder sb = new StringBuilder();
    while ((line = bf.readLine()) != null) {
        sb.append(line);
    }

    System.out.println(sb.toString());

    System.out.println(content);
}

@Downvoter please explain. This answer is correct. – user207421 Aug 14 '20 at 07:37 — user207421, Aug 14 '20 at 07:37

read file from resource Java

1 Answers1