I had two different codes:
uint8_t buf[10];
writeSomeDataInto(&buf);
readSomeDataFrom(buf);
and it was working correctly, but then I realized that I was sendind the address of the buffer, not the buffer itself, and changed it to:
uint8_t buf[10];
writeSomeDataInto(buf);
readSomeDataFrom(buf);
and the result was exactly the same.
Why am I getting the same result? Is &buf and buf the same thing in this context? It is actually does not make sense to me that the compiler would allocate some space for the buffer pointer &buf address.
How is this different from the code below?
uint8_t * ptr;
writeDataInto(&ptr); //actually sending the pointer of a pointer.
readDataFrom(ptr);
Comparing it also with pointer to functions such as "void myfunc(); //myfunc == &myfunc
I feel that I'm missing some concept about how C works.
