what is the condition to return the items that doesn't match

Question

const arr1 = ["605116", "703771", "726664", "612706", "475557", "521034", "547016"];
const arr2 = ["605116", "703771"];

arr1.map(item1 => arr2.map(item2 => (item1===item2) ? console.log(item1) : null))

result :

605116 703771

what is the condition to return the items that don't match?

expected results:

"726664", "612706", "475557", "521034", "547016"

need to be jsx compatible

BTW you are abusing `.map()` here. Please use a different array method for such a task, for example `.filter()` — Sebastian Kaczmarek, Aug 19 '20 at 09:12
that other example doesn't help i cant use for loops in jsx. The second map can be switched with a filter whatewer — Bogdan, Aug 19 '20 at 09:27
You haven't mentioned anything about JSX. That is why you should always provide all the necessary details for others to be able to answer the question. — Sebastian Kaczmarek, Aug 19 '20 at 09:29

score 3 · Answer 1 · answered Aug 19 '20 at 09:10

3

You can use filter and includes.

const arr1 = ["605116", "703771", "726664", "612706", "475557", "521034", "547016"];
const arr2 = ["605116", "703771"];

console.log(arr1.filter(item=>!arr2.includes(item)));

answered Aug 19 '20 at 09:10

Jax-p

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score 1 · Answer 2 · edited Aug 19 '20 at 09:23

1

console.log(array1.filter(item => array2.indexOf(item) == -1));

edited Aug 19 '20 at 09:23

Suraj Rao

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answered Aug 19 '20 at 09:22

ali ajouz

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what is the condition to return the items that doesn't match

2 Answers2