How can I parse string date with regex?

Question

I have 3 possible string date.

I have to parse the date string with Regex

date = "13.06.2020"
date2 = "13-06-2020"
date3 = "13/06/2020"

for i in [date,date2,date3]:
    finder = re.findall(r'something',i) #I try findall but I think it doesn't work.
    print("day : " + finder[0])
    print("month : " + finder[1])
    print("year : " + finder[2])

It supposed to give that output for all possibilities. I figure out with Datetime but I can't use it. I have use re library

day:13
month:06
year:2020

Do you guys have any suggestions?

Please share what you have tried? Also, any specific reason why you must use regex? — Gilad Green, Aug 19 '20 at 11:56
@GiladGreen Hi man. I am just trying scrape date from a website and each website has different types. I have to parse for all possibilities. — Murat Demir, Aug 19 '20 at 12:19
@MuratDemir Still wondering why you must use regex. Is this for an assignment? — alani, Aug 19 '20 at 12:25

score 0 · Accepted Answer · answered Aug 19 '20 at 12:06

0

Try this

for i in [date,date2,date3]:
    finder = re.findall(r'(\d{1,2})[\.\-\/](\d{2})[\.\-\/](\d{4})',i)
    print("day : " + finder[0][0])
    print("month : " + finder[0][1])
    print("year : " + finder[0][2])

answered Aug 19 '20 at 12:06

SeemsLegit

97
3

score 0 · Answer 2 · answered Aug 19 '20 at 12:14

0

Avoid using regex to parse date strings. Use parser.parse from dateutil module (which you can install through pip using the cmd pip install python-dateutil)

>>> from dateutil import parser
>>> for date_str in [date,date2,date3]:
...     dt = parser.parse(date_str)
...     print(f"day : {dt.day}, month: {dt.month}, year: {dt.year}")
... 
day : 13, month: 6, year: 2020
day : 13, month: 6, year: 2020
day : 13, month: 6, year: 2020

answered Aug 19 '20 at 12:14

Prem Anand

2,469
16
16

I have to use regex. The task's general-purpose regex, I don't know why. Thanks alot – Murat Demir Aug 19 '20 at 12:22

How can I parse string date with regex?

2 Answers2