Why float, double and long double gives the same output?

Asked Aug 20 '20 at 17:22

Active Aug 20 '20 at 17:22

Viewed 42 times

It might seem a dumb question but I am very confused about it. I wrote a simple program as follow:

#include<iostream>
using namespace std;
 int main() 
{ 
float a = 12.555555555555;
double b = 12.555555555555;
long double c = 12.555555555555;

cout <<a<<endl; 
cout <<b<<endl;
cout <<c<<endl;
return 0; 
}

Although I am using different data type with each variable but the result of output is same for all these variables and that is 12.5556. I was expecting different precision for double and long double as compared to float. I am using DevC++ IDE.

asked Aug 20 '20 at 17:22

Awais Kamran

1

By default `std::cout` only shows a few decimal points. The linked question explains how to print mode decimal points. – François Andrieux Aug 20 '20 at 17:23
Next time you better check true values in a debugger – Alexey S. Larionov Aug 20 '20 at 17:24
What were you basing your expectation on? It's better when you don't know to have minimal expectations, you'll learn quicker that way. – john Aug 20 '20 at 17:25

Why float, double and long double gives the same output?

0 Answers0