Is there a way I could put this error into a variable in python?

Question

I have the code here:

import traceback

try:
    raise TypeError("Oups!")
except Exception as err:
    try:
        raise TypeError("Again !?!")
    except:
        pass
    traceback.print_tb(err.__traceback__)

I am not sure how I could put the error into a variable with the same format. The error looks like:

  File "C:/Users/user/PycharmProjects/project/file.py", line 4, in <module>
    raise TypeError("Oups!")

Can anyone help?

score -1 · Answer 1 · answered Aug 20 '20 at 17:26

-1

The raise keyword throws the exception upwards, here quitting the programm as it reaches top level. You can save an exception like any other type as its just a class. Try this: smthing = TypeError("new error")

answered Aug 20 '20 at 17:26

DownloadPizza

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That only returns `new error`, not the formatted error. – Top Of Tech Aug 20 '20 at 17:29
Obviously it also works with the variable err. – DownloadPizza Aug 21 '20 at 10:18

Is there a way I could put this error into a variable in python?

1 Answers1