How to create a zip archive in Python without creating files on file system?

Question

One easy way is to create a directory and populate it with files. Then archive and compress that directory into a zip file called, say, file.zip. But this approach is needless since my files are in memory already, and needing to save them to disk is excessive.

Is it possible that I create the directory structure right in memory, without saving the unzipped files/directories? So that I end up saving only the final file.zip (without the intermediate stage of saving files/directories on file system)?

Possible duplicate of https://stackoverflow.com/questions/2463770/python-in-memory-zip-library — S4rt-H4K, Aug 25 '20 at 21:21
@S4rt-H4K I don't think it says how to add a directory structure to it. E.g. add a folder/directory to it. Thoughts? — caveman, Aug 26 '20 at 09:45
Just 1 directory. Or maybe multiple. Not quite sure about their number yet. — caveman, Aug 26 '20 at 11:44

Martim · Answer 1 · 2022-06-06T15:32:38.110

1

You can use zipfile:

from zipfile import ZipFile

with ZipFile("file.zip", "w") as zip_file:
    zip_file.writestr("root/file.json", json.dumps(data))
    zip_file.writestr("README.txt", "hello world")

edited Jun 06 '22 at 15:32

answered May 24 '22 at 04:54

Martim

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This worked for me, but there is a typo: in the import `Zipfile` should be `ZipFile` (with a capital F) – Alexandra Espichán Jun 02 '22 at 17:45

How to create a zip archive in Python without creating files on file system?

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