Storing a sorted array in Java, not understanding .clone() Java

Question

I am trying to store a sorted array separate from the original array. I need to be able to access both arrays without altering the original in anyway. I have tried to understand how to to .clone but I can't seem to understand what I am doing wrong. I have my code below, I am passing an array from above into this method and want to sort and store it. Am I even close to being correct here?

public static double sortArray(int[] array) {
        //Sort the array
        Object tempObj = array.clone();
        Arrays.sort(tempObj);
        sortedArray[] = tempObj;

`int[] sortedArray = array.clone(); Arrays.sort(sortedArray);` — , Aug 28 '20 at 00:13
https://stackoverflow.com/questions/14149733/clone-method-for-java-arrays This answer explains the use of the clone() method — G 1, Aug 28 '20 at 00:21

beastlyCoder · Answer 1 · 2020-08-28T00:16:20.507

0

You can do this with the new sorted array, using java 8 streams:

int[] newArr = Arrays.stream(array).sorted().toArray(int[]::new);

Then change your method return type to int[]:

public static int[] sortArray(int[] array) 
{
    int[] newArr = Arrays.stream(array).sorted().toArray(int[]::new); 
    return newArr; 
}

edited Aug 28 '20 at 00:16

answered Aug 28 '20 at 00:14

beastlyCoder

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you could use `return` immediately without creating `int[] newArr` reference :) – Nowhere Man Aug 28 '20 at 00:28
yes, but he said he wanted to keep track of both array's so i just did that for clarity – beastlyCoder Aug 28 '20 at 00:33

Storing a sorted array in Java, not understanding .clone() Java

1 Answers1