Passed arguments are not interpreted in curl command

Question

I have a shell script that only does a curl command to notify my Discord server about an issue. I pass two arguments which I want to add into the data body of the curl command but their values are not interpreted.

My script call:

./notifier.sh usernameArg contentArg

My script:

#!/bin/bash

curl -X POST -H "Content-Type: application/json" -d '{"username": "$1", "content": "$2"}' "https://<discord webhook url>"

But all it sends is {"username": "$1", "content": "$2"}. I also tried to use ${1} and ${2} with same result.

Thanks for your help in advance!

Variables are not expanded inside single quotes. – Barmar Aug 28 '20 at 11:01 — Barmar, Aug 28 '20 at 11:01

score 1 · Accepted Answer · answered Aug 28 '20 at 11:05

1

Try this instead.

#!/bin/bash

curl -X POST -H "Content-Type: application/json" -d '{"username": "'$1'", "content": "'$2'"}' "https://<discord webhook url>"

answered Aug 28 '20 at 11:05

redInk

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Passed arguments are not interpreted in curl command

1 Answers1