I have a list like this.
a = ['\n', 'a', 'b', '\n', 'c', '\n']
As far as I know, the remove, pop, delete method only removes one by one.
If I want to remove all'\n' from this list, the only way to do this is to use remove via a for or a while loop using remove method? Or is there a specific method?
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AuccKhan
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list comprehension `a = [x for x in a if x != '\n']` is your friend – Jean-François Fabre Aug 28 '20 at 13:25
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@Jean-FrançoisFabre Not really. There may be other references to the list. – alani Aug 28 '20 at 13:25
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2okay then: `a[:] = [x for x in a if x != '\n']` (but OP didn't specify that part) – Jean-François Fabre Aug 28 '20 at 13:26
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How about:
a = ['\n', 'a', 'b', '\n', 'c', '\n']
list(filter(('\n').__ne__, a))
Raymond Reddington
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but it's covered already here: https://stackoverflow.com/a/1157160/6451573. I would be cool if people voted to close instead of FFGITW answering. And list comprehensions are generally used, not this clunky list+filter+__ne__ stuff – Jean-François Fabre Aug 28 '20 at 13:30