Print Line Starting with a String

Question

I have a file that prints line by line if match is in line, and if the string "Expected" is in line. However, I want the line to start with match instead of the actual beginning of the line.

This is the code I have

F = open(path,'r')
writestring = ''
for line in F:
    if match in line:
        if 'Expected' in line:
            writestring = writestring+line+'\n'

I have tried that and it did not work since the lines do not start with match or "expected" — sawpythonnewbie, Aug 31 '20 at 20:37
Then you need to explain more clearly what you are trying to do. — khelwood, Aug 31 '20 at 20:40
Do you mean that you want to print a _substring_ of the line starting from `match`? — khelwood, Aug 31 '20 at 20:45
The lines are very long. Example of a line: `[2020-Aug-01 19:51:25.337][C][TAL][DUT: 188703_772_1][8948][DiagsLogger::Error, Line 90]match Expected: 8.041418; Actual: -0.029907` I want to only print `match Expected: 8.041418; Actual: -0.029907` Not the whole thing — sawpythonnewbie, Aug 31 '20 at 20:46
If I understand correctly, you want to find a substring of each line and print it instead of the entire line. I suggest you learn about regular expressions and capturing groups. You can use this to find a specific part of a string. — Code-Apprentice, Aug 31 '20 at 21:42

score 1 · Accepted Answer · answered Aug 31 '20 at 20:48

To print line starting from the point where match occurs, you can do this:

print(line[line.index(match):])

line.index(match) returns the index where match occurs in line, and line[line.index(match):] is the substring from that index to the end of the string.

Print Line Starting with a String

1 Answers1