How do I check if the answer of the division shown in the code is divisible by 2?

Question

I'm aiming to check if b / a's answer is divisible by 2, and if it is - it will print yes.

   a = int(input())
   b = int(input())
   if b / a #is divisible by 2
         print("Yes.")
   else:
         print("No.")

thank you! im still new the percentage sign's use in python and it confuses me tbh. — Mr. Wheatly Core, Sep 02 '20 at 08:24
Does this answer your question? [How do you check whether a number is divisible by another number (Python)?](https://stackoverflow.com/questions/8002217/how-do-you-check-whether-a-number-is-divisible-by-another-number-python) — Sowjanya R Bhat, Sep 02 '20 at 08:24

score 2 · Answer 1 · edited Sep 02 '20 at 08:23

2

How about this?

a = int(input())
b = int(input())
if (b / a) % 2 == 0:
    print("yes")
else:
    print("no")

edited Sep 02 '20 at 08:23

VisioN

answered Sep 02 '20 at 08:22

Daisuke Akagawa

score 0 · Answer 2 · answered Sep 02 '20 at 08:24

0

Use modulo(%) so for this example if (b/a)%2 == 0:

answered Sep 02 '20 at 08:24

score 0 · Answer 3 · answered Sep 02 '20 at 09:16

You can also use the ternary operator to combine the if/else statement into a single print statement like this:

print("yes" if (b / a) % 2 == 0 else "no")

You can also do it in a branchless fashion to decrease complexity and increase speed:

print("yes" * ((b/a) % 2 == 0) + "no" * (not (b/a) % 2 == 0))

This works because False has an int value of 0, therefore "text" * False = ""
Similarly, "text" * True = "text"

3 Answers3