How do you take multiple named parameters in a function and pass them to a dictionary in python?

Question

One of the coolest things I've learned about python recently is that a dictionary can take parameters like this:

dict(red=3,blue=2,yellow=5)

How could I make a function that takes arguments in the same fashion and pass them to a dictionary? I don't want to declare red, blue, or yellow as individual parameters. Ideally, this would take in named parameters of any kind.

I've already tried:

def foo(*args):

...and it doesn't like how the parameters are named.

Another thought I had was extending the dictionary definition so I could still use init of the dictionary, but I wouldn't know how to do that either.

Try `**kwargs`. Check this post: https://stackoverflow.com/questions/51751929/python-can-i-pass-a-defined-dictionary-to-kwargs — Mike67, Sep 05 '20 at 23:00

score 0 · Answer 1 · answered Sep 05 '20 at 23:06

0

I think you were on the right track with *args, but what I think you want to use is **kwargs.

def make_dict(**kwargs):
    return dict(**kwargs)

myDict = make_dict(red=2, cyan=43)
print(myDict)

it should print {'red': 2, 'cyan': 43}

answered Sep 05 '20 at 23:06

Josh Anibal

146
5

How do you take multiple named parameters in a function and pass them to a dictionary in python?

1 Answers1