How to fetch a random image link from a site in Python?

Question

I am new to web scraping I don't know much about it. I have made a bit of program which fetches a random image link from a website , But I get a list of links while doing so I am not getting a single link

HERE'S MY CODE

from bs4 import BeautifulSoup
import urllib.parse
from urllib.request import urlopen,Request
import random


requester = {'User-Agent': 'Mozilla/5.0'}
req=Request("https://image.com",headers=requester)
u =urlopen(req)


soup = BeautifulSoup(u.read(), features="lxml")



links = soup.find_all('a')

images =[]
for img in soup.findAll('img'):
    images.append(img.get('src'))
    img=random.choice(images)
    
    print(img)

HERE'S THE OUTPUT

https://www.bing.com/th?id=OHR.LongIsland_EN-US4283514207_1920x1080.jpg&rf=LaDigue_1920x1080.jpg&pid=hp
https://www.bing.com/th?id=OHR.BeaverDam_EN-US4184266799_1920x1080.jpg&rf=LaDigue_1920x1080.jpg&pid=hp
https://www.bing.com/th?id=OHR.PicoIsland_EN-US3959411167_1920x1080.jpg&rf=LaDigue_1920x1080.jpg&pid=hp
https://www.bing.com/th?id=OHR.LongIsland_EN-US4283514207_1920x1080.jpg&rf=LaDigue_1920x1080.jpg&pid=hp
https://www.bing.com/th?id=OHR.FinancialTowers_EN-US3881212547_1920x1080.jpg&rf=LaDigue_1920x1080.jpg&pid=hp
https://www.bing.com/th?id=OHR.LongIsland_EN-US4283514207_1920x1080.jpg&rf=LaDigue_1920x1080.jpg&pid=hp
https://www.bing.com/th?id=OHR.BeaverDam_EN-US4184266799_1920x1080.jpg&rf=LaDigue_1920x1080.jpg&pid=hp
https://www.bing.com/th?id=OHR.PicoIsland_EN-US3959411167_1920x1080.jpg&rf=LaDigue_1920x1080.jpg&pid=hp
https://www.bing.com/th?id=OHR.BeaverDam_EN-US4184266799_1920x1080.jpg&rf=LaDigue_1920x1080.jpg&pid=hp
https://www.bing.com/th?id=OHR.LongIsland_EN-US4283514207_1920x1080.jpg&rf=LaDigue_1920x1080.jpg&pid=hp
https://www.bing.com/th?id=OHR.LongIsland_EN-US4283514207_1920x1080.jpg&rf=LaDigue_1920x1080.jpg&pid=hp
https://www.bing.com/th?id=OHR.FinancialTowers_EN-US3881212547_1920x1080.jpg&rf=LaDigue_1920x1080.jpg&pid=hp
https://www.bing.com/th?id=OHR.PRNLCavern_EN-US7693319589_1920x1080.jpg&rf=LaDigue_1920x1080.jpg&pid=hp
https://www.bing.com/th?id=OHR.FinancialTowers_EN-US3881212547_1920x1080.jpg&rf=LaDigue_1920x1080.jpg&pid=hp
https://www.bing.com/th?id=OHR.BeaverDam_EN-US4184266799_1920x1080.jpg&rf=LaDigue_1920x1080.jpg&pid=hp
https://www.bing.com/th?id=OHR.PicoIsland_EN-US3959411167_1920x1080.jpg&rf=LaDigue_1920x1080.jpg&pid=hp
https://www.bing.com/th?id=OHR.FinancialTowers_EN-US3881212547_1920x1080.jpg&rf=LaDigue_1920x1080.jpg&pid=hp

I only want a single link from the above list also link should be randomize

https://stackoverflow.com/questions/306400/how-to-randomly-select-an-item-from-a-list — Dave Ankin, Sep 06 '20 at 09:00
The problem is that I want only one link I also used random.choice() but I am unable to think why a list of link appears — Saksham Kushwaha, Sep 06 '20 at 09:01
Did you mean for your last two lines of code to be indented? It seems like they shouldn't be. — Aviv Shai, Sep 06 '20 at 09:03
replace the final for loop with: `print(random.choice(soup.findAll('img')))` — Or Y, Sep 06 '20 at 09:03
Just unindent your last two lines of code, you're running your choice making in for loop which is not right — Venkat Ramana, Sep 06 '20 at 09:04

score 1 · Accepted Answer · answered Sep 06 '20 at 09:06

1

Use img=random.choice(images) out of the for loop.

images =[]
for img in soup.findAll('img'):
    images.append(img.get('src'))

img=random.choice(images)    
print(img)

answered Sep 06 '20 at 09:06

Osadhi Virochana

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What was the reason for the above output – Saksham Kushwaha Sep 06 '20 at 13:22
It is because you are getting random URL(`img=random.choice(images)`) in for loop and you are printing(`print(img)`) in for loop. – Osadhi Virochana Sep 08 '20 at 08:38
Thanks for telling me – Saksham Kushwaha Sep 08 '20 at 17:01

How to fetch a random image link from a site in Python?

1 Answers1