How to call extension function via same name instance function in kotlin

Question

For example

open class TestClass

fun TestClass.testFunc(): String = "ext"

now in another file I write:

import xx.xx.testFunc as rename

class OverTestClass : TestClass() {

    fun testFunc(): String {
        return "OverTestClass - " + rename()
    }
}

You can see I rename TestClass.testFunc() as rename() so I can call TestClass.testFunc() in OverTestClass. But this is not cool, what the way I want to is like this:

return "OverTestClass - " + super.testFunc()

Is it possible?

I know this problem is upside down，the reason I want to this is: I am writing a lib used both in java and kotlin, I don't want write java like:

XxxKt.func(obj)

I want to:

obj.func(func)

So I put func as an instance function. and implement directly by its "super" extension function

Does this answer your question? [extension function in a kotlin using super](https://stackoverflow.com/questions/51170152/extension-function-in-a-kotlin-using-super) — flaxel, Sep 06 '20 at 10:35

score 2 · Answer 1 · answered Sep 06 '20 at 12:05

2

I'd try up-casting to the TestClass:

class OverTestClass : TestClass() {

    fun testFunc(): String {
        return "OverTestClass - " + (this as TestClass).testFunc()
    }
}

answered Sep 06 '20 at 12:05

Mafor

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How to call extension function via same name instance function in kotlin

1 Answers1