"bad variable name" and "word expected" error in shell script

Question

I'm creating a shell script to perform basic math operations using WSL. Im using ubuntu terminal for this purpose.

#!/bin/bash
echo "+ : Addition (a+b)"
echo "- : Subtraction (a-b)"
echo "* : Multiplication (a*b)"
echo "/ : Division (a/b)"
read -p "Choose operation: " op
read -p "Enter value of a: " a
read -p "Enter value of b: " b
case $op in
"+")
echo $a "+" $b "=" $((a+b))
;;
"-")
echo $a "-" $b "=" $((a-b))
;;
"*")
echo $a "*" $b "=" $((a*b))
;;
"/")
echo $a "/" $b "=" $((a/b))
;;
esac

this is the code. Im executing this code using command

sh add.sh

"add.sh" is the file name

and I'm getting this error message

A bit of google https://www.google.com/search?q=How+do+I+remove+dos+line+endingds%3F should help you. In command line with `dos2unix` program — KamilCuk, Sep 07 '20 at 06:52
ok "dos2unix" command worked for me. Thank you very much. @KamilCuk — Ritesh Shakya, Sep 07 '20 at 07:54

score 0 · Answer 1 · answered Sep 07 '20 at 06:39

0

you have dos line endings. You can use fromdos to get rid of them

fromdos test.txt

The above example would take a MS-DOS or Microsoft Windows file or other file with different line separators and format the file with new line separators to be read in Linux and Unix.

Ref: https://stackoverflow.com/a/12509995/1118978

answered Sep 07 '20 at 06:39

Derviş Kayımbaşıoğlu

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Thanks. I used "dos2unix" command and it worked and "formdos" worked as well! – Ritesh Shakya Sep 07 '20 at 07:59
If this answer is useful for you, please consider to upvote and/or mark it as answer. thank you – Derviş Kayımbaşıoğlu Sep 07 '20 at 08:01

"bad variable name" and "word expected" error in shell script

1 Answers1