Alice is taking a cryptography class and finding anagrams to be very useful. We consider two strings to be anagrams of each other if the first string's letters can be rearranged to form the second string. In other words, both strings must contain the same exact letters in the same exact frequency For example, bacdc and dcbac are anagrams, but bacdc and dcbad are not.
Alice decides on an encryption scheme involving two large strings where encryption is dependent on the minimum number of character deletions required to make the two strings anagrams. Can you help her find this number?
Given two strings, and , that may or may not be of the same length, determine the minimum number of character deletions required to make and anagrams. Any characters can be deleted from either of the strings.
For example, if and , we can delete from string and from string so that both remaining strings are and which are anagrams.
Function Description
Complete the makeAnagram function in the editor below. It must return an integer representing the minimum total characters that must be deleted to make the strings anagrams.
makeAnagram has the following parameter(s):
a: a string b: a string Input Format
The first line contains a single string, . The second line contains a single string, .
Constraints
The strings and consist of lowercase English alphabetic letters ascii[a-z]. Output Format
Print a single integer denoting the number of characters you must delete to make the two strings anagrams of each other.
Sample Input
cde abc Sample Output
4 Explanation
We delete the following characters from our two strings to turn them into anagrams of each other:
Remove d and e from cde to get c. Remove a and b from abc to get c. We must delete characters to make both strings anagrams, so we print on a new line.
****my question is can someone please explain what is the use of int ct = count.containsKey(ch) ? count.get(ch) : 0;
public class Solution {
public static int numberNeeded(String first, String second) {
Map<Character, Integer> count = new HashMap<>();
for( char ch: first.toCharArray() ) {
int ct = count.containsKey(ch) ? count.get(ch) : 0;
count.put(ch, (ct + 1));
}
for( char ch: second.toCharArray() ) {
int ct = count.containsKey(ch) ? count.get(ch) : 0;
count.put(ch, (ct - 1));
}
List<Integer> values = new ArrayList<>( count.values() );
int total = 0;
for( Integer v: values ) {
total += Math.abs(v);
}
return total;
}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
String a = in.next();
String b = in.next();
System.out.println(numberNeeded(a, b));
} }
