IndentationError: expected an indented block cannot loop script

Question

I am trying to make a loop so that the script generates hash constantly

from bitcoin import *
import os
import hashlib
import base58

while True:
    priv =  random_key()
    pubkey = privtopub(priv)
    compress_pubkey = False
    
 
    if (compress_pubkey):
    if (ord(pubkey[-2:].decode('hex')) % 2 == 0):
        pubkey_compressed = '02'
    else:
        pubkey_compressed = '03'
    pubkey_compressed += pubkey[2:66]
    hex_str = bytearray.fromhex(pubkey_compressed)
    else:
        hex_str = bytearray.fromhex(pubkey)
 
key_hash = hash160(hex_str)

I am using Python 3 and I am getting the error:

    if (ord(pubkey[-2:].decode('hex')) % 2 == 0):
     ^
IndentationError: expected an indented block

TL:DR Select this if and the line below and press TAB on your keyboard. Python needs indentation for code inside an if block — solid.py, Sep 13 '20 at 09:09

score 0 · Answer 1 · answered Sep 13 '20 at 09:10

0

You are getting an error because first if statement does not have anything in it, you can use pass keyword to remove an error or remove the if statement if you don't need it(see comments in code)

from bitcoin import *
import os
import hashlib
import base58

while True:
    priv =  random_key()
    pubkey = privtopub(priv)
    compress_pubkey = False
    
 
    if (compress_pubkey): #error
        pass #add something hereor add pass keyword to remove error
    if (ord(pubkey[-2:].decode('hex')) % 2 == 0):
        pubkey_compressed = '02'
    else:
        pubkey_compressed = '03'
        hex_str = bytearray.fromhex(pubkey) # you can't have more than one else
    pubkey_compressed += pubkey[2:66]
    hex_str = bytearray.fromhex(pubkey_compressed)
 
key_hash = hash160(hex_str)

answered Sep 13 '20 at 09:10

Sarthak Kumar

304
5
16

Now I am getting the error: else: ^ SyntaxError: invalid syntax – FOLBY Sep 13 '20 at 09:16
you have 2 `else` statements in a single if look carefully in the solution I've combined your both else into one, as that was a syntax error. – Sarthak Kumar Sep 13 '20 at 09:40
I am getting the error: AttributeError: 'str' object has no attribute 'decode' – FOLBY Sep 13 '20 at 09:52
Writes that this is not true: if (ord (pubkey [-2:]. Decode ('hex'))% 2 == 0): – FOLBY Sep 13 '20 at 09:53

IndentationError: expected an indented block cannot loop script

1 Answers1