scanf() production problems in Python

Question

I wanted to try writing functions of a language to a different one. I opt for C to Python, and here is what I've done so far.

Code:

def printf(text, *args):
    print(text % args, end = '')

def scanf(text, *args):
    args = input(text % args)
    return args

name = None
scanf("What's your name? %s", name)
printf("Hello, %s.\n", name)

Result:

What's your name? NoneBoy
Hello, Boy.

I have 3 problems regarding this question:

scanf doesn't actually print out the variable to be inputted.
I have to implement a variable with no value, but unlike C, where you could just write int result;, you must write it as result = None and my function would print None as well.
It never returned any value.

Are there any solutions I can use to fix these?

https://stackoverflow.com/questions/2175080/sscanf-in-python — Alexander Dmitriev, Sep 14 '20 at 09:10
@AlexanderDmitriev yes it's right. Thanks a lot of sharing this . — Vishal Sheth, Sep 14 '20 at 09:50

score 0 · Accepted Answer · answered Sep 14 '20 at 09:45

You can use static variables for updating any value inside the function.

class Example:
    name = "None"

def printf(text, args):
    print(text % args, end = '')

def scanf(text, args):
    Example.name = input(text)

scanf("What's your name? ", name)
printf("Hello, %s.\n", Example.name)

There are other pre-build functions to use. This is the example of the user-defined functions. If you want to use a pre-defined function. Please let me know.

scanf() production problems in Python

1 Answers1