Ex:
vector<string> myVec = {apple, banana, grape}
How can I print these elements as an ordered list using a range-based loop
Output:
1 apple
2 banana
3 grape
Ex:
vector<string> myVec = {apple, banana, grape}
How can I print these elements as an ordered list using a range-based loop
Output:
1 apple
2 banana
3 grape
A variation of Jeffrey's answer, but without additional variable:
for (const auto& s : myVec)
{
std::cout << &s - &myVec[0] << " " << s << "\n";
}
This, of course, prints a "correct" 0-based index. Feel free to add 1
to it :)
Using boost ranges really simplifies things Live Demo
using namespace boost::adaptors;
std::vector<std::string> myVec = {"apple", "banana", "grape"};
for (const auto& element : myVec | indexed(1))
{
std::cout << element.index() << " " << element.value() << "\n";
}
Produces
1 apple
2 banana
3 grape
You are looking for
size_t position = 1;
for(const auto& s: myVec)
{
std::cout << position << " " << s << "\n";
position++;
}
as in
#include <iostream>
#include <string>
#include <vector>
using std::vector;
using std::string;
vector<string> myVec = {"apple", "banana", "grape"};
int main()
{
size_t position = 1;
for(const auto& s: myVec)
{
std::cout << position << " " << s << "\n";
position++;
}
}
This would be a good issue for the original for
loop:
const size_t quantity = myVec.size();
for (unsigned int i = 0; i < quantity; ++i)
{
cout << (i + 1) << " " << myVec[i] << "\n";
}
Simple, effective. Don't knock the old stuff. :-)