How To convert a number in a string into a list with every number is alone

Question

i wanted to make a code which you put a random number using Input (Should be more than two dights) and the program make it a list which is every dight alone, or with more precise I wont to spell the numbers

i've tried this and i don't found any solution

Ex of what i want to do:

input = "57472"
output = [5, 7, 4, 7, 2]

Welcome to StackOverflow, I suggest you post what you have tried. — Ivor Denham-Dyson, Sep 18 '20 at 10:58
`[int(x) for x in inp]`? *Never* use `input` as variable name, as it possibly overwrites the `input` method! — AnsFourtyTwo, Sep 18 '20 at 11:00

score 0 · Answer 1 · answered Sep 18 '20 at 10:57

0

A simple [int(x) for x in input] would do, if I understand the question correctly.

For list comprehension, look at eg: https://www.programiz.com/python-programming/list-comprehension

answered Sep 18 '20 at 10:57

Matej Murin

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score 0 · Answer 2 · answered Sep 18 '20 at 11:02

0

Try: m_list = input.split('')

It will split the string into it's chars, if you want the elements to be int just convert each of them

answered Sep 18 '20 at 11:02

Yossi Levi

1,258
1
4
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How To convert a number in a string into a list with every number is alone

2 Answers2