How to caculate time diffs between two date times?

Question

diff = reference_time - topic_time
hour = round((reference_time-topic_time) / datetime.timedelta(hours=1))

if reference_time = '2020-08-23 07:00:10' and topic_time = '2020-08-22 00:00:00', the 'diff' variable is:

days = 1
seconds = 25210

The 'hour' conversion code make the hour = 31, which seems incorrect. The max diff should be less than 24 hours in one day. How to calculate time diffs and convert to hours in this case?

related? https://stackoverflow.com/questions/538666/format-timedelta-to-string — FObersteiner, Sep 19 '20 at 11:39

bilginyuksel · Accepted Answer · 2020-09-19T06:23:38.007

0

import datetime

firstTime = datetime.datetime.utcnow()
secondTime = datetime.datetime.utcnow() + datetime.timedelta(hours=5)
diff = secondTime - firstTime
hours = diff.total_seconds() // 3600
print(hours) # Answer is 5


reference_time = datetime.datetime(2020,8,23,7)
topic_time = datetime.datetime(2020,8,22,0)
hours = (reference_time - topic_time).total_seconds() // 3600
days = hours // 24
hours = hours - (days*24)
print('days: %d, hours: %d' % (days, hours) ) # days:1, hours:7

edited Sep 19 '20 at 06:23

answered Sep 19 '20 at 06:16

bilginyuksel

160
2
7

Can you explain why 'hours = hours - (days*24)' gives the right answer? – marlon Sep 20 '20 at 03:10

How to caculate time diffs between two date times?

1 Answers1