How to floor numbers to whole number in python

Question

I am wondering how can I floor 1,999,999 to 1,000,000 or 2,000,108 to 2,000,000 in python? I used math.floor() but it's just for removing decimal part.

score 1 · Accepted Answer · answered Sep 20 '20 at 18:53

1

Just do it like this:

math.floor(num / 1000000) * 1000000

e.g.:

>>> num=1999999
>>> math.floor(num / 1000000) * 1000000
1000000.0
>>> num=2000108
>>> math.floor(num / 1000000) * 1000000
2000000.0

answered Sep 20 '20 at 18:53

Yuchen

30,852
26
164
234

1

`num = 111; math.floor(num / 1000000) * 1000000` gives `0`, which is not at all what the OP expects (100). – Thierry Lathuille Sep 20 '20 at 19:06

score 0 · Answer 2 · answered Sep 20 '20 at 19:03

0

To round down positive integer to first digit

from math import floor

def r(n):
    gr = 10 ** (len(str(n))-1)
    return floor(n / gr) * gr

for i in [199_999, 200_100, 2_100, 315]:
    print(r(i))

Output

answered Sep 20 '20 at 19:03

Michael Szczesny

4,911
5
15
32

score 0 · Answer 3 · answered Sep 20 '20 at 19:05

def floor_integer(num):
    l = str(num)
    return int(l[0]) * pow(10, len(l) - 1)

I think that will fits your needs.

print(floor_integer(5))
# 5

print(floor_integer(133))
# 100

print(floor_integer(1543))
# 1000

print(floor_integer(488765))
# 400000

print(floor_integer(1999999))
# 1000000

print(floor_integer(2000108))
# 2000000

How to floor numbers to whole number in python

3 Answers3