Go from aaaa to zzzz python

Question

I need to find a way to brute-force from aaaa to zzzz using python (aaaa, aaab, aaac... zzzz). Similar to 0000 to 9999. Is there a "magical" way to do that using loops and lists?

Have you looked into [itertools.combinations](https://docs.python.org/3.8/library/itertools.html#itertools.combinations)? — rassar, Sep 21 '20 at 14:05
See [this](https://stackoverflow.com/questions/7074051/what-is-the-best-way-to-generate-all-possible-three-letter-strings) — namgold, Sep 21 '20 at 14:05
charses = 'abcdefghijklmnopqrstuvwxyz' listilist= [] for current in xrange(10): a = [i for i in your_list] for y in xrange(current): a = [x+i for i in charses for x in a] listilist= listilist+a — Tahalich, Sep 21 '20 at 14:05
@Tahalich please updated in the question, not post in comment — namgold, Sep 21 '20 at 14:06
@Tahalich edit the question and show what you've tried there, not in comment — phuclv, Sep 21 '20 at 14:06

Brian61354270 · Answer 1 · 2020-09-21T14:31:45.163

You can accomplish this succinctly with using itertools.product:

import itertools
import string

for elem in itertools.product(string.ascii_lowercase, repeat=5):
    ...

Here's a sample for the first 30 values yielded by this approach:

>>> values = itertools.product(string.ascii_lowercase, repeat=5)
>>> print(list(itertools.islice(values, 30)))
[
    ('a', 'a', 'a', 'a', 'a'), 
    ('a', 'a', 'a', 'a', 'b'), 
    ('a', 'a', 'a', 'a', 'c'), 
    # --Snip -- 
    ('a', 'a', 'a', 'a', 'x'), 
    ('a', 'a', 'a', 'a', 'y'), 
    ('a', 'a', 'a', 'a', 'z'), 
    ('a', 'a', 'a', 'b', 'a'), 
    ('a', 'a', 'a', 'b', 'b'), 
    ('a', 'a', 'a', 'b', 'c'), 
    ('a', 'a', 'a', 'b', 'd')
]

Note that there are 26**5 == 11881376 values in this sequence, so you probably don't want to store them all in a list. On my system, such a list it occupies roughly 100 MiB.

score 0 · Accepted Answer · answered Sep 21 '20 at 14:18

This is a very "basic" example:

chars = 'abcdefghijklmnopqrstuvwxyz'
my_list = []

for c1 in chars:
    for c2 in chars:
        for c3 in chars:
            for c4 in chars:
                my_list.append(c1+c2+c3+c4)
                
print(my_list)

score 0 · Answer 3 · answered Sep 21 '20 at 14:22

0

It's not easy to know what you consider "magical", but I don't see the magic in loops.
Here is one variation:

cs = 'abcdefghijklmnopqrstuvwxyz'
list(map(''.join, [(a,b,c,d) for a in cs for b in cs for c in cs for d in cs]))

answered Sep 21 '20 at 14:22

molbdnilo

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Go from aaaa to zzzz python

3 Answers3