There is one way to do this that involves using expression trees. This way you build the Boolean expression yourself. It's pretty straight forward the tricky part though is that you need to rebase the parameters because otherwise it is going to refer the original lambda expression. See below for an example:
static void Main(string[] args)
{
var source = new List<int> { 1, 2, 3 };
var any = new List<Expression<Func<int, bool>>>();
any.Add(x => x == 1);
any.Add(x => x == 3);
foreach (var item in source.AsQueryable().WhereDisjunction(any))
{
Console.WriteLine(item);
}
}
class RewriteSingleParameterUsage : ExpressionVisitor
{
public ParameterExpression Parameter { get; set; }
protected override Expression VisitParameter(ParameterExpression node)
{
return Parameter;
}
}
public static IQueryable<T> WhereDisjunction<T>(this IQueryable<T> source, IList<Expression<Func<T, bool>>> any)
{
switch (any.Count)
{
case 0: return source;
case 1: return source.Where(any[0]);
default:
var p = Expression.Parameter(any[0].Parameters[0].Type, any[0].Parameters[0].Name);
var rw = new RewriteSingleParameterUsage { Parameter = p };
var expr = rw.Visit(any[0].Body);
for (int i = 1; i < any.Count; i++)
{
expr = Expression.Or(expr, rw.Visit(any[i].Body));
}
return source.Where(Expression.Lambda<Func<T, bool>>(expr, p));
}
}
In the above example I'm being very harsh, I'm effectively replacing any parameter with this single new parameter that is being used to create the new expression. However, given the signature of this extension method it shouldn't really be possible to call this method with parameters such that it would cause an error. It is however going to be a problem if you involve more than one parameter.