How to apply AND operator to a python bytes object

Question

I have a 4 bytes value that need to be applied a masking

x = b'\x22\x22\x22\x22'
mask = b'\xff\xff\x00\x00'

I tried x & mask but show unsupported operand type(s) error.

TypeError: unsupported operand type(s) for &: 'bytes' and 'bytes'

Please advice how I can apply the masking here?

Best

score 1 · Accepted Answer · answered Sep 23 '20 at 14:10

1

 b"".join([bytes([a & b]) for a,b in zip(x,mask)])

result:

b'""\x00\x00'

answered Sep 23 '20 at 14:10

Or Y

@Tomerikoo Well, `"` in ascii is 34 in decimal which is 0x22 in hex, I just copied the output from IPython – Or Y Sep 23 '20 at 14:17
Yeah, that is correct. But actually I need to convert it back to short int. Maybe just a memoryview()? can you advice? Basically masking masking, I wish to take the first 2 as a uint val_1 and the last 2 as a uint val_2 – J_yang Sep 23 '20 at 14:19
@J_yang you can use ```int.from_bytes``` for that - for example: ```int.from_bytes(b'\xff\xff', byteorder='big')``` you can split the ```bytes``` every two bytes in a list for that – Or Y Sep 23 '20 at 14:25

1 Answers1