Return array element NOT present in the second array

Question

I need to return the element of first array NOT present in the second, return empty array if both are present in second array

arr1 = [' name', 'email']

arr2 = [ 'name', 'card_number', 'role', 'age' ]

expect to return ['email'] in this example

tried to use filter but didn't succeed.

anyone can help, please?

Can you please post your attempt with `.filter()`? – Nick Parsons Sep 24 '20 at 12:03 — Nick Parsons, Sep 24 '20 at 12:03
is space here `' name'` a typo? – Nina Scholz Sep 24 '20 at 12:04 — Nina Scholz, Sep 24 '20 at 12:04

score 3 · Accepted Answer · answered Sep 24 '20 at 12:04

3

You could look if the other array does not includ the value for filtering.

const
    arr1 = ['name', 'email'],
    arr2 = ['name', 'card_number', 'role', 'age'],
    result = arr1.filter(v => !arr2.includes(v));

console.log(result);

answered Sep 24 '20 at 12:04

Nina Scholz

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Return array element NOT present in the second array

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