Bash variable number in ascending order

Question

I have a variable named "event_id" that represents an event number. I want to run the script with a change of this variable from number 1 to number 65000. This means that the script will run in cycles and each time the variable "event_id" will increase the number by 1 until it reaches 65000.

event_id="1"
curl -k -u api:1234 https://localhost 'search=index=test eventid='$event_id''

Please your help

michjnich · Accepted Answer · 2020-09-24T17:30:36.837

0

Just put it in a loop

for ((i = 1 ; i < 65001 ; i++)); do
    curl -k -u api:1234 https://localhost "search=index=test eventid='${i}'"
done

edited Sep 24 '20 at 17:30

answered Sep 24 '20 at 17:19

michjnich

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I suggest to use `for ((i = 1 ; i <= 65000 ; i++))`. – Cyrus Sep 24 '20 at 17:26
1

also `; do` is necessary. – thanasisp Sep 24 '20 at 17:27
I get some error: ./script.sh: line 2: syntax error near unexpected token `curl' – OmZ Sep 24 '20 at 17:28
Sorry, yes, missed the "; do" becuase I was focusing on the loop :) Probably want to start from 1 too, but tweak the numbers as needed. Honestly, this is a google question, not a SO question anyway ... – michjnich Sep 24 '20 at 17:31

Bash variable number in ascending order

1 Answers1