Adding integer to a list using append and for loop in python

Question

I am new to python stuck with the issue of not getting the list after appending using the *args to fetch every element.

def has_33(*args):
    m=[]
    for i in args:
        m = m.append(i)
    print(m)
has_33([1,3,3])

output

None

abhigyanj · Answer 1 · 2020-09-26T03:28:50.567

1

You can do something like this:

def has_33(*args):
    m=list(args)
    print(m)
has_33([1,3,3])

And if you don't need the list you can do this:

def has_33(*args):
    m=list(args)
    n = []
    for l in m:
        for elem in l:
            n.append(elem)

    print(n)
has_33([1,3,3])

edited Sep 26 '20 at 03:28

answered Sep 26 '20 at 03:21

abhigyanj

1

Any reason why the above coding is not fetching the elements – Sagar Dixit Sep 26 '20 at 03:23
@SagarDixit It's because `append()` returns None – abhigyanj Sep 26 '20 at 03:23
Output to your code:[[1, 3, 3]] – Sagar Dixit Sep 26 '20 at 03:24
The output is `[[1, 3, 3]]` – abhigyanj Sep 26 '20 at 03:24
But I don't need a nested list instead a single list – Sagar Dixit Sep 26 '20 at 03:26
@SagarDixit Added that as well – abhigyanj Sep 26 '20 at 03:29

score 1 · Answer 2 · answered Sep 26 '20 at 03:24

1

Remove m=m.append(i) and write like this m.append(i) This works.

answered Sep 26 '20 at 03:24

Varun Kumar

But I am getting a nested list any ways of getting a single list – Sagar Dixit Sep 26 '20 at 03:29
Yes,this works because m is initially a empty list and you are appending an element to that list – Varun Kumar Sep 26 '20 at 03:30
Remove * in the function parameter ```has_33(args)``` – Varun Kumar Sep 26 '20 at 03:31

2 Answers2