How do I receive a "Share URL" from browser?

Question

I read this ( How do I handle the browser's "share page" intent in android? ) which I can get the Share link to detect my app, now how do I get Activity to receive the URL?

Found Answer:

Intent intent = getIntent();
if (savedInstanceState == null && intent != null) {
    Log.d(TAG, "intent != null");

    if (intent.getAction().equals(Intent.ACTION_SEND)) {
        Log.d(TAG, "intent.getAction().equals(Intent.ACTION_SEND)");
        String message = intent.getStringExtra(Intent.EXTRA_TEXT);
        messageText.setText(message);
        receiverText.requestFocus();
    }
}

score 11 · Accepted Answer · answered Aug 30 '11 at 18:53

11

When your application receives the "Share page" from the browser, you could also get the title of the webpage:

String subject = intent.getStringExtra(Intent.EXTRA_SUBJECT);

answered Aug 30 '11 at 18:53

poplitea

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Reno · Answer 2 · 2011-06-21T10:29:33.580

5

Once you have created an intent filter, your activity should pop up in the list of activities listening to the share link. Then use this in your activity:

String url = getIntent().getStringExtra(Intent.EXTRA_TEXT);

edited Jun 21 '11 at 10:29

answered Jun 20 '11 at 16:54

Reno

33,594
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102

Thanks, this is what I put in my OnCreate for my Main Activity: 'Uri myI = getIntent().getData(); String myItext = myI.toString(); mEditText.setText(myItext);' But it force closes once I try to convert it to string (line #2) – James Jun 20 '11 at 17:44
@James Oh my bad, when I answered this I had no access to an emulator/device to test it. I was going to suggest using extra string, but you've found the answer. Good work – Reno Jun 21 '11 at 10:27

How do I receive a "Share URL" from browser?

2 Answers2

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