How can I list only directory names, with no trailing "/"?

Question

by doing the following command in the folder

ls -d */ | cut -f1 -d'/'

I get entries like:

env1
env2
env3
env4

how I can use cat/grep or yq/jq or any other alternative command(s) instead of the above command?

What use are you later making of these entries? Iterating over them in a shell script? Or just printing to stdout? — Charles Duffy, Sep 30 '20 at 20:32
What you want to achieve? Just list the directories in the current directory? — kofemann, Sep 30 '20 at 20:33
@kofemann I'm using this command as a script in my groovy code using in helm file to print the list of environments in the output, using this command it print a list of env sequentially, but I need to print them in parallel — sasan, Sep 30 '20 at 20:37
note that that's an innately unsafe thing to do: directory names can have spaces. How can you tell the difference between two different directory names printed on the same line, and one name with a space? (The same argument is why line-separating filenames is a bad idea as well, since newlines are _also_ legal inside names; Doing It Right calls for using the NUL character, which is the _only_ character that can't exist in a name, as terminator). — Charles Duffy, Sep 30 '20 at 20:54

score 1 · Answer 1 · answered Sep 30 '20 at 20:33

1

for dir in */; do
  echo "${dir%/}"
done

answered Sep 30 '20 at 20:33

Charles Duffy

can I ask you also briefly explain about your answer? – sasan Sep 30 '20 at 20:38

score 0 · Accepted Answer · answered Sep 30 '20 at 21:10

There are several options. You can use the tree command with the options:

# d: list only directories
# i: no print of indention line
# L: max display depth of the directory tree
tree -di -L 1 "$(pwd)"

Or you can also use the grep command to get the directories and the command awk:

# F: input field separator
# $9: print the ninth column of the output
ls -l | grep "^d" | awk -F" " '{print $9}'

Or you can use the sed command to remove the slash:

# structure: s|regexp|replacement|flags
# g: apply the replacement to all matches to the regexp, not just the first
ls -d */ | sed 's|[/]||g'

I found this solutions in this post.

2 Answers2