Javascript checking, if array element equals var?

Question

I have an array like this:

var str = "This is an example sentence with the number 1";
var array = str.split(' ');

// array[8] should be 1

Now i want to check, if a certain variable is the same as the value of array[8]. Therefor i thought I could use:

var checkingnumber = 1;

if(array[8] === checkingnumber) {
    console.log("success");
    return
}

This doesnt seem to work in my Code. So could anyone help me, how to fix that ?

`===` also checks for types. the result of `str.split()` is an array of strings and not numbers (like `checkingnumber`), so your comparison fails — Sirko, Oct 03 '20 at 07:55
One question - just to play devil's advocate here - is it **always** the 9th word in the sentence? Could it be the **last** word? Could it be somewhere else in the sentence? — ATD, Oct 03 '20 at 08:29

Dominik · Answer 1 · 2020-10-03T08:03:58.770

1

The resulting array will be strings and === will compare the type as well. Use == or parseInt to make sure you compare apples with apples.

var checkingnumber = 1;

if(parseInt(array[8]) === checkingnumber) {
    console.log("success");
    return
}

edited Oct 03 '20 at 08:03

answered Oct 03 '20 at 07:55

Dominik

Thanks a lot ! Thats exactly what I needed and it works! :) – Frosty Oct 03 '20 at 08:02
No worries. Feel free to mark this as the answer ;) – Dominik Oct 03 '20 at 08:03
You mean number of apples with number of apples. – pilchard Oct 03 '20 at 08:42

1 Answers1