how to iterate over a list and assign items to a variables using python

Question

How to iterate over a list and assign each item to a variable until now i am able to iterate over the list and print all the items but i want to store each item in a variable in order to use it later like so.

Here i am hardcoding the variables... what i want is to assign values during the iteration.

code:

tl = pd.unique(df[item1].tolist())

var1 = df[item1][df[item1]==tl[0]]
var2 = df[item1][df[item1]==tl[1]]
var3 = df[item1][df[item1]==tl[2]]
var4 =df[item1][df[item1]==tl[3]]


print("number of var1  is: {}".format(len(var1)))
print("number of var2  is: {}".format(len(var2)))
print("number of var3  is: {}".format(len(var3)))
print("number of var4 is: {}".format(len(var4)))

what i want :

tl = pd.unique(df[item1].tolist())
                for column in tl:
                    print(column)

Please provide a sample input and the desired output, it's very hard to tell what you want. — Chris, Oct 07 '20 at 18:46
i did ...i want to assign each item of the list to a variable as i showed in the first chunk of code — Georges, Oct 07 '20 at 18:48
the name will be `the value of the item` where the iterated list will contain distinct values — Georges, Oct 07 '20 at 18:50
@Georges **don't do this** Don't dynamically create variables. Use a *container*. Like a `list` in this case — juanpa.arrivillaga, Oct 07 '20 at 19:07
In this case, just `var = [df[item1][df[item1] == t] for t in tl]` — juanpa.arrivillaga, Oct 07 '20 at 19:09
your comment is the perfect answer but how to use the created variable from the list comprehension in this : `slice_pie=[format(100*len(var0)/df.shape[0]), format(100*len(var1)/df.shape[0]),format(100*len(var2)/df.shape[0]), format(100*len(var3)/df.shape[0])]` — Georges, Oct 07 '20 at 19:17

score 0 · Answer 1 · answered Oct 07 '20 at 18:49

0

for index, row in df.T.iterrows():
    for c, x in enumerate(row.unique()):
        print(f'number of row{c+1} is: {x}')

answered Oct 07 '20 at 18:49

Chris

15,819
3
24
37

RMPR · Answer 2 · 2020-10-07T20:10:07.597

0

Assuming n is the length of the list (you can have that easily) You can replace all this:

var1 = df[item1][df[item1]==tl[0]]
var2 = df[item1][df[item1]==tl[1]]
var3 = df[item1][df[item1]==tl[2]]
var4 = df[item1][df[item1]==tl[3]]
...
varn = df[item1][df[item1]==tl[n]]

With a list comprehension:

var = [df[item1][df[item1]==t] for t in tl]

Now to print:

for i in range(n):
    print(f"number of var{i}  is: {len(var[i])}")

edited Oct 07 '20 at 20:10

answered Oct 07 '20 at 18:50

RMPR

3,368
4
19
31

the range is not fix its the `len` of the list – Georges Oct 07 '20 at 18:52
Answer updated with a variable `n` containing the length of the list – RMPR Oct 07 '20 at 18:54
Don't use `n`, just `[df[item1][df[item1] == t] for t in tl]` – juanpa.arrivillaga Oct 07 '20 at 19:08

how to iterate over a list and assign items to a variables using python

code:

what i want :

2 Answers2