The IF statement got it wrong?

Question

Hey I'm a beginner at javascript, and I've come across this issue. It seems like the IF statement recognizes the variable as something it isn't. I think it has something to do with the OR operator?

let variabel = `a variable with random value`;

if (variabel === `a` || `b`){
    console.log(`the variable is the same as a or b`)
} else {
    console.log(`not the same`)
}

So it does say the variable is the same as a or b in the console. So the if statement is true? But it isn't?

Your if statement is testing whether `variable === 'a'` OR _"b" is true_. Because "b" is [truthy](https://developer.mozilla.org/en-US/docs/Glossary/Truthy), the condition evaluates to true. — ray, Oct 07 '20 at 21:48
Your expression is evaluated as ```(variabel === `a`) || (`b`)```. — Felix Kling, Oct 07 '20 at 21:48
Keeping in mind that the template literals aren't getting you anything in this use case. — Taplar, Oct 07 '20 at 21:49

score 2 · Answer 1 · answered Oct 07 '20 at 21:47

2

The correct syntax is:

let variabel = `a variable with random value`;

if (variabel === `a` || variabel === `b`){
    console.log(`the variable is the same as a or b`)
} else {
    console.log(`not the same`)
}

answered Oct 07 '20 at 21:47

welp, rookie mistakes. I feel like I will be making those more haha – Emile Caron Oct 07 '20 at 21:51

score 0 · Answer 2 · answered Oct 07 '20 at 21:50

0

Correct use of OR is this way

let variabel = `a variable with random value`;

if (variabel === `a` || variabel === `b`){
    console.log(`the variable is the same as a or b`)
} else {
    console.log(`not the same`)
}

answered Oct 07 '20 at 21:50

Jakub Štellner

106
8

The IF statement got it wrong?

2 Answers2