How do I retrieve * literal using read command?

Asked Oct 08 '20 at 21:17

Active Oct 08 '20 at 21:19

Viewed 34 times

I have a script that receives input from the user. One of the possible values I want to retrieve is the literal *. It seems the shell is intercepting it and executing so that I'm getting a list of all the file names.

while   read -p "Enter operand: " operandTwo
        echo "Argument: $operandTwo"           
        echo "Argument: $(echo $operandTwo)"
        [ $operandTwo != X ]
        echo "Result: $?"
do...

This is the output:

Argument: *
Argument: File1 File2 File3
./script: line 20: [: too many arguments
Result: 2

Is the comparison being made here between File1 File2 File3 and X? How do I make a comparison between * and X instead?

edited Oct 08 '20 at 21:19

asked Oct 08 '20 at 21:17

jjkl

1

Run your script through https://shellcheck.net and follow its advice. – Shawn Oct 08 '20 at 21:18
1

tldr `$(echo $operandTwo)` is redundant and the variable expansion should be quoted – wjandrea Oct 08 '20 at 21:21

How do I retrieve * literal using read command?

0 Answers0