The following is a popup message I get on an Android Emulator running 1.5 -->

Question

The application Android Sample Mobile App (process com.mycompany.mobile.android) has stopped unexpectedly. Please try again.

This occurs when I click on the device's menu button; the menu comes up with an exit icon...which does the following when selected..

public boolean onOptionsItemSelected(MenuItem item) {
    // Handle item selection
    switch (item.getItemId()) {
    case R.id.exit:
             this.finish();
        return true;
    default:
        return super.onOptionsItemSelected(item);
    }
}

In other Android versions this code works fine.

score 0 · Answer 1 · answered Jun 21 '11 at 16:51

Post your stacktrace or LogCat and we can see what's wrong.

My hunch is that it's either calling super out of order for that API level, or that finishing an activity inside of a switch may not be handled correctly, or that that item mightbe a null ref. more info plz.

score 0 · Answer 2 · answered Jun 21 '11 at 16:52

Android 1.5 is one of the oldest versions (if not the oldest), most if not all handsets have 1.6 or greater. I would not recommend breaking your head on this. Also there are very significant differences between 1.5 to 1.6, the API's are a lot more consistent from 1.6. Not the answer you want, but just my two cents.

score 0 · Answer 3 · edited May 23 '17 at 11:48

0

Just a piece of advice: it seems like you are adding an exit button to your application.
Beware that it is advised NOT TO add an Exit Button to Android Applications: Is quitting an application frowned upon?

edited May 23 '17 at 11:48

Community

1
1

answered Jun 21 '11 at 17:29

pandre

6,685
7
42
50

The following is a popup message I get on an Android Emulator running 1.5 -->

3 Answers3