isolating grouped digits from integer input

Question

My aim is to be able to input a large (6 digit) number into a terminal and for it to return the middle two digits, swapped.

My code is as follows:

a = int(input())
b = int(input())
c = int(input())
d = int(input())
e = int(input())
f = int(input())

addition = ((a * 0) + (b * 0) + (d * 10))
addition_two = ((c) + (e * 0) + (f * 0))
print(addition + addition_2)

I'm unsure of how to adjust this in order for it to work correctly.

Do you understand how the decimal number system works? Why do you multiply the input values with 0? — mkrieger1, Oct 10 '20 at 18:43

score 0 · Answer 1 · answered Oct 10 '20 at 18:43

0

I don't understand all the complexity. If you only want the middle two digits (and they're swapped), you can simply use:

n = input("Enter number: ")
ans = n[2:4]
return int(ans) //if you want int type, else ans would suffice as str

answered Oct 10 '20 at 18:43

Abhinav Mathur

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If it solves your purpose, consider upvoting/marking it as the accepted answer – Abhinav Mathur Oct 11 '20 at 06:46

score 0 · Answer 2 · answered Oct 10 '20 at 18:45

Ask for inputs until it is 6 long and only consists of digits. there is no need to convert anything to a number, you can work with the string directly by slicing it correctly:

while True:
    k = input("6 digit number")
    if not all(c.isdigit() for c in k) or len(k) != 6:
        print("Not a six digit number")
    else:
        break

# string slicing:
#   first 2 letters
#   reversed 4th and 3rd letter
#   remaining letters
print(k[:2] + k[3:1:-1] + k[4:])

See Asking the user for input until they give a valid response and Understanding slice notation

isolating grouped digits from integer input

2 Answers2