How to recalculate variable?

Question

I'm thinking of making a variable calculate every time I call/use them? Is that even possible?

int myvalue = rn.nextInt(100 - 1 + 1) + 1;
System.out.println("call myvalue: " + myvalue);
System.out.println("call myvalue again: " + myvalue);
System.out.println("call myvalue the third time: " + myvalue);

Does this answer your question? [how to call a java method using a variable name?](https://stackoverflow.com/questions/4138527/how-to-call-a-java-method-using-a-variable-name) — Ivo Merchiers, Oct 12 '20 at 08:29

score 1 · Accepted Answer · answered Oct 12 '20 at 05:01

Option 1, create a method:

static int myvalue(Random rn) {
    return rn.nextInt(100 - 1 + 1) + 1;
}

System.out.println("call myvalue: " + myvalue(rn));
System.out.println("call myvalue again: " + myvalue(rn));
System.out.println("call myvalue the third time: " + myvalue(rn));

Option 2, use a lambda expression (Java 8+):

IntSupplier myvalue = () -> rn.nextInt(100 - 1 + 1) + 1;
System.out.println("call myvalue: " + myvalue.getAsInt());
System.out.println("call myvalue again: " + myvalue.getAsInt());
System.out.println("call myvalue the third time: " + myvalue.getAsInt());

score 0 · Answer 2 · answered Oct 12 '20 at 05:02

Create a method which will return int like this:

static int myvalue()
{ 
    Random rn= new Random();  
    return rn.nextInt(100 - 1 + 1) + 1;
}

and call it in System.out.println():

public static void main(String[] args) 
{                       
  System.out.println("call myvalue: " + myvalue());
  System.out.println("call myvalue again: " + myvalue()); 
  System.out.println("call myvalue the third time: " + myvalue());
}

How to recalculate variable?

2 Answers2